JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Hard

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Analyzing +4 | -1

The sum of all the products of the first

n

natural numbers taken two at a time is

View answer and explanation

Correct option: A

\frac{1}{{24}}n\left( {n - 1} \right)\left( {n + 1} \right)\left( {3n + 2} \right)

Option A (

\frac{1}{{24}}n(n - 1)(n + 1)(3n + 2)

) is correct because the sum of all products of the first n natural numbers taken two at a time is

\frac{1}{{24}}n(n - 1)(n + 1)(3n + 2)

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