JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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\frac{1}{{1!\left( {n - 1} \right)!}} + \frac{1}{{3!\left( {n - 3} \right)!}} + \frac{1}{{5!\left( {n - 5} \right)!}} + ...

is equal to

View answer and explanation

Correct option: C

\frac{{{2^{n - 1}}}}{{n!}}

for all values of

n

Option C (

\frac{{{2^{n - 1}}}}{{n!}}

for all values of

n

) is correct because the given expression can be simplified using binomial coefficients.

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