JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Easy

1 of 1

Analyzing +4 | -1

The function,

f(x) = (3x - 7){x^{2/3}},\,\,x \in R

, is increasing for all

x

lying in

View answer and explanation

Correct option: A

\left( { - \infty ,\,0} \right) \cup \left( {\frac{{14}}{{15}},\,\infty } \right)

Option A (

\left( { - \infty ,\,0} \right) \cup \left( {\frac{{14}}{{15}},\,\infty } \right)

) is correct because the function is increasing when its derivative is greater than or equal to zero, which occurs in the specified intervals.

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f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)