JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

\lim\limits_{x \to 0} {\left( {{\text{cosec}}\,\,x} \right)^{\frac{1}{{{{\log }_e}x}}}}

equals

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Correct option: C

\frac{1}{e}

Option C (

\frac{1}{e}

) is correct because by applying L'Hopital's rule to the logarithm of the expression, we find the limit is -1, thus the original limit is

\frac{1}{e}

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