Let $f\left( 2 \right) = 4$ and $f'\left( 2 \right) = 4$. Then, $\mathop {\lim }\limits_{x \to 2} \frac{{xf\left( 2 \right) - 2f\left( x \right)}}{{x - 2}}$ is given by

JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1

Let

f\left( 2 \right) = 4

and

f'\left( 2 \right) = 4

. Then,

\lim\limits_{x \to 2} \frac{{xf\left( 2 \right) - 2f\left( x \right)}}{{x - 2}}

is given by

View answer and explanation

Correct option: C

- 4

Option C (

-4

) is correct because it is obtained by applying L'Hopital's rule or by rewriting the limit in terms of the derivative of f(x).

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