JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1

Let

g(x)=\cos x^2, f(x)=\sqrt{x}

, and

\alpha, \beta(\alpha < \beta)

be the roots of the quadratic equation

18 x^2-9 \pi x+\pi^2=0

. Then the area (in sq. units) bounded by the curve

y=g o f(x)

and the lines

x=\alpha

and

x=\beta

, is

View answer and explanation

Correct option: D

\frac{1}{2}(\sqrt{3}-1)

Option D (

\frac{1}{2}(\sqrt{3}-1)

) is correct because it is the area under the cosine curve between the roots of the given quadratic equation.

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