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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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1x+1+12(x+1)2+13(x+1)3+…∞=\frac{1}{x+1}+\frac{1}{2(x+1)^2}+\frac{1}{3(x+1)^3}+\ldots \infty= ?
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Correct option: A
log⁡v(1+1x)\log _v\left(1+\frac{1}{x}\right)
Option A (log⁡v(1+1x)\log _v\left(1+\frac{{1}}{{x}}\right)) is correct because the given series is a logarithmic series expansion, and simplifying it results in the expression log⁡e(1+1x)\log _e\left(1+\frac{{1}}{{x}}\right).

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