Skip to main content
Back to CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

NEET UG CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

1 Medium
1 of 1
Application +4 | -1
First and second ionisation energies of magnesium are 7.646 and 15.035eV15.035 \mathrm{eV} respectively. The amount of energy in kJ\mathrm{kJ} needed to convert all the atoms of magnesium into Mg2+\mathrm{Mg}^{2+} ions present in 12mg12 \mathrm{mg} of magnesium vapours is :

[Given : 1eV=96.5 kJ mol−11 \mathrm{eV}=96.5 \mathrm{~kJ} \mathrm{~mol}^{-1} ]
View answer and explanation
Correct option: A
1.1
Option A (1.1) is correct because it calculates the total ionization energy for converting all Mg atoms in 12mg to Mg²⁺ ions, considering both first and second ionization energies.

More Questions from CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.