JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Analyzing +4 | -1

The angle between the curves

y = {a^x}

and

y = {b^x}

is equal to

View answer and explanation

Correct option: D

{\tan ^{ - 1}}\left( {\left| {\frac{{\log a - \log b}}{{1 + \log a\log b}}} \right|\;} \right)\;

Option D (

{\tan ^{ - 1}}\left( {\left| {\frac{{\log a - \log b}}{{1 + \log a\log b}}} \right|\\;} \right)\\;

) is correct because it represents the angle between the curves, calculated using the derivatives at the point of intersection.

More Questions from TANGENTS & NORMALS

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z