For $x \in R\,\,\mathop {\lim }\limits_{x \to \infty } {\left( {\frac{{x - 3}}{{x + 2}}} \right)^x}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

For

x \in R\,\,\lim\limits_{x \to \infty } {\left( {\frac{{x - 3}}{{x + 2}}} \right)^x}

is equal to

View answer and explanation

Correct option: C

{e^{ - 5}}

Option C (

{e^{ - 5}}

) is correct because by rewriting the expression and using the limit definition of

e

, the limit evaluates to

{e^{ - 5}}

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