If $2A + 3B = \left[ {\begin{array}{*{20}{c}} {2\; - 1\;\;4}\\ {3\;\;\;\;\;\;2\;\;5} \end{array}} \right]{\rm{and\;}}A + 2B = \left[ {\begin{array}{*{20}{c}} {5\;\;0\;\;3}\\ {1\;\;6\;\;2} \end{array}} \right],\;{\rm{then}}\;\;B\;{\rm{is}}$

$\left[ {\begin{array}{*{20}{c}} 8&1&2\\ { - 1}&{10}&{ - 1} \end{array}} \right]$

$\left[ {\begin{array}{*{20}{c}} 8&{ - 1}&2\\ { - 1}&{10}&{ - 1} \end{array}} \right]$

$\left[ {\begin{array}{*{20}{c}} 8&1&{ - 2}\\ { - 1}&{10}&{ - 1} \end{array}} \right]$

$\left[ {\begin{array}{*{20}{c}} 8&1&2\\ 1&{10}&1 \end{array}} \right]$

JEE MATHEMATICS MCQ: MATRICES

1 Easy

1 of 1

Application +4 | -1

2A + 3B = \left[ {\begin{array}{cccccccccccccccccccc} {2\; - 1\;\;4}\\ {3\;\;\;\;\;\;2\;\;5} \end{array}} \right]\mathrm{and\;}A + 2B = \left[ {\begin{array}{cccccccccccccccccccc} {5\;\;0\;\;3}\\ {1\;\;6\;\;2} \end{array}} \right],\;\mathrm{then}\;\;B\;\mathrm{is}

View answer and explanation

Correct option: C

\left[ {\begin{array}{cccccccccccccccccccc} 8&1&2\\ { - 1}&{10}&{ - 1} \end{array}} \right]

Option A is correct because solving the system of linear equations for matrices A and B results in the matrix B =

\left[ {\begin{array}{cccccccccccccccccccc} 8&1&2\\ { - 1}&{10}&{ - 1} \end{array}} \right]