If $\cos \,\,{\rm{\theta }} = - \frac{1}{{\sqrt {2\;} }}$ and $\tan \,\,{\rm{\theta }} = 1$, then the general value of ${\rm{\theta }}$ is

$2\left( {n + 1} \right){\rm{\pi }} + \frac{{\rm{\pi }}}{4}$

$2n{\rm{\pi }} + \frac{{\rm{\pi }}}{4}$

$n{\rm{\pi }} + \frac{{\rm{\pi }}}{4}$

$n{\rm{\pi }} \pm \frac{{\rm{\pi }}}{4}$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Analyzing +4 | -1

\cos \,\,\mathrm{\theta } = - \frac{1}{{\sqrt {2\;} }}

and

\tan \,\,\mathrm{\theta } = 1

, then the general value of

\mathrm{\theta }

View answer and explanation

Correct option: B

2\left( {n + 1} \right)\mathrm{\pi } + \frac{\mathrm{\pi }}{4}

The correct answer is B (

2(n+1)\pi + \frac{\pi}{4}

) because it represents the general solution that satisfies both the cosine and tangent conditions.

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