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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
∫π/6π/3  dx1+cot⁡  x\int \nolimits_{\pi /6}^{\pi /3} \,\,\frac{{dx}}{{1 + \sqrt {\cot \,\,x} }} is equal to
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Correct option: C
π12\frac{\mathrm{\pi }}{12}
Option C (π12\frac{\mathrm{\pi }}{{12}}) is correct because the definite integral is evaluated using the property ∫ab f  (x)  dx=∫ab f  (a+b−x)  dx\int \nolimits_a^b \,f\,\,\left( x \right)\,\,dx = \int \nolimits_a^b \,f\,\,\left( {a + b - x} \right)\,\,dx.

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