Skip to main content
Back to CURRENT ELECTRICITY

JEE PHYSICS MCQ: CURRENT ELECTRICITY

1 Medium
1 of 1
Application +4 | -1
An inductor (L=20 H)(L=20 \mathrm{\,H}), a resistor (R=100 Ω)(R=100 \, \Omega) and a battery ( E=10 VE=10 \mathrm{~V} ) are connected in series. After a long time, the circuit is short-circuited and then the battery is disconnected Find the current in the Circuit at I ns after short circuiting
View answer and explanation
Correct option: D
6.7×10−4 A6.7 \times 10^{-4} \mathrm{~A}
Option D (6.7×10−4 A6.7 \times 10^{-4} \mathrm{~A}) is correct because it is calculated using the formula for current decay in an LR circuit after short-circuiting.

More Questions from CURRENT ELECTRICITY

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.