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JEE MATHEMATICS MCQ: COMBINATIONS

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A person goes for an examination in which there are four papers with a maximum of m marks from each paper. The number of ways in which one can get 2m2m marks, is
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Correct option: C
13(m+1)(2m2+4m+3)\frac{1}{3}\left( {m + 1} \right)\left( {2{m^2} + 4m + 3} \right)
Option C (13(m+1)(2m2+4m+3)\frac{1}{3}(m + 1)(2m^2 + 4m + 3)) is correct because it represents the number of ways to obtain 2m marks from four papers, each with a maximum of m marks.

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