The value $\mathop {\lim }\limits_{x \to a} {\left( {\frac{{\sin x}}{{\sin a}}} \right)^{\frac{1}{{x - a}}}}$, is

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

The value

\lim\limits_{x \to a} {\left( {\frac{{\sin x}}{{\sin a}}} \right)^{\frac{1}{{x - a}}}}

, is

View answer and explanation

Correct option: C

{e^{\cot a}}

Option C (

{e^{\cot a}}

) is correct because it follows from applying L'Hopital's rule after rewriting the limit in exponential form.

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