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NEET UG PHYSICS MCQ: MAGNETISM AND MATTER

1 Medium
1 of 1
Application +4 | -1
A current of 1A is flowing on the sides of an equilateral triangle of side 4.5×10−2m4.5 \times {10^{ - 2}}m. The magnetic field at the centre of the triangle will be:
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Correct option: A
4×10−5 Wb/m24 \times {10^{ - 5}}\,Wb/{m^2}
Option A is correct because the magnetic field at the center of the triangle is calculated using the formula B = (3μ₀I)/(2πd), where d is the perpendicular distance from the side to the center, resulting in 4 × 10⁻⁵ Wb/m².

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