The multiplicative inverse of $(6+5 i)^2$ is

$\frac{11}{60}-\frac{60}{61} i$

$\frac{11}{61}-\frac{60}{61} i$

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

The multiplicative inverse of

(6+5 i)^2

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct because the multiplicative inverse of

(6+5i)^2

\frac{11}{(61)^2} - \frac{60}{(61)^2}i

, which is not among the given options.

Practice All Chapter MCQs →

{\left| {1 - i} \right|^x} = {2^x}

|z|=1

z \neq \pm 1

z, \frac{z}{1-z^2}

\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

a \neq 0

\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}