JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

\sin \,\,5\;x + \sin \,\,3\;x + \sin \,\,x = 0

then the value of

x

other than zero, lying between

0 \le x \le \frac{\pi }{2}

View answer and explanation

Correct option: C

\frac{\pi }{3}

Option C is correct because the value of x is found by solving the trigonometric equation using sum-to-product formulas.

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\left( {x,\,y} \right)

x,\,\,y \in \left[ {0,10} \right]

\left( {\sqrt {{{\sin }^2} - \sin \,\,x + \frac{1}{2}} } \right){2^{{{\sec }^2}y}}\,\, \cdot \,\, \le 1

\mathrm{X}

\theta \rightarrow \frac{\pi}{2}

\sin x+\cos x=\frac{\sqrt{7}}{2}

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0 < x < \pi

\cos x+\sin x=\frac{1}{2}

\tan x