The density of a metal at normal pressure is $\rho$. Its density when it is subjected to an excess pressure $p$ is $\rho^{\prime}$. If $B$ is the bulk modulus of the metal, then the ratio $\rho^{\prime} / \rho$ is

NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

1 Hard

1 of 1

Application +4 | -1

The density of a metal at normal pressure is

\rho

. Its density when it is subjected to an excess pressure

p

\rho^{\prime}

. If

B

is the bulk modulus of the metal, then the ratio

\rho^{\prime} / \rho

View answer and explanation

Correct option: D

\frac{1}{(1-p / B)}

Option D (

\frac{{1}}{{(1-p / B)}}

) is correct because it relates the change in density to the applied pressure and the bulk modulus.

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