JEE MATHEMATICS MCQ: MAXIMA & MINIMA

1 Hard

1 of 1

Application +4 | -1

The minimum value of

px + qy

when

xy = {r^2}

, is

View answer and explanation

Correct option: A

2r\sqrt {pq}

Option A (

2r\sqrt {pq}

) is correct because it represents the minimum value obtained by minimizing the expression

px + qy

subject to the constraint

xy = r^2

using calculus.

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