JEE PHYSICS MCQ: WAVES

1 Medium

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Application +4 | -1

A plane longitudinal wave of angular frequency

1000 \,{rad} {s}^{-1}

is travelling along negative

x

-direction in a homogeneous gaseous medium of density

\rho=1 {~kg} {~m}^{-3}

. Intensity of the wave is

I=10^{-10} {Wm}^{-2}

and the maximum pressure change is

2 \times 10^{-4} {Nm}^{-2}

. Then, displacement equation is

View answer and explanation

Correct option: B

y=10^{-9} \cos (1000 t+5 x)

Option B (

y=10^{-9} \cos (1000 t+5 x)

) is correct because it represents a wave traveling in the negative x-direction with the correct amplitude and wave number.

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3\,\,kHz

0.5

f\mathrm{ }Hz

V\mathrm{ }m/sec

0.2\,\,V

y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}},

(– \mathrm{ve}) \,x

y = f(kx +\omega t),

X

0.01\,\,s

5 \mathrm{~m}

245 \mathrm{~g}

1 \mathrm{~kg}

g=980 \mathrm{~cm} \mathrm{~s}^{-2}

T

V