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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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A dye emits 50%50 \% of the absorbed energy as fluorescence. If the number of quanta absorbed and emitted out is in the ratio 1:21: 2 and it absorbs the radiation of wavelength ' xx ' A∘\mathop {\text{A}}\limits^ \circ, then the wavelength of the emitted radiation will be
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Correct option: C
4x A∘4 x\,\mathop {\text{A}}\limits^ \circ
Option C (4x A∘4 x\,\mathop {\text{A}}\limits^ \circ) is correct because the emitted wavelength is four times the absorbed wavelength, derived from the energy and quantum ratio relationship.

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