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JEE MATHEMATICS MCQ: COMBINATIONS

1 Easy
1 of 1
Application +4 | -1
Find nC21{ }^n C_{21}, if nC10=nC11{ }^n C_{10}={ }^n C_{11}.
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Correct option: A
1
Option A (1) is correct because given nC10=nC11{ }^n C_{10}={ }^n C_{11}, we find n=21n=21, and 21C21=1{ }^{21} C_{21}=1.

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