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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1

A charged particle of mass

0.003 \mathrm{~g}

is held stationary is space by placing it in a downward direction of electric field of

6 \times 10^4 \mathrm{~N} / \mathrm{C}

. Then the magnitude of the charge is

View answer and explanation

Correct option: B

5 \times 10^{-10} \mathrm{C}

Option B (

5 \times 10^{-10} \mathrm{C}

) is correct because the charge is calculated by equating the electric force to the gravitational force.

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