1 gram of sodium hydroxide was treated with $25 \mathrm{~mL}$ of $0.75 \mathrm{~M} \, {HCl}$ solution, the mass of sodium hydroxide left unreacted is equal to

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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Application +4 | -1

1 gram of sodium hydroxide was treated with

25 \mathrm{~mL}

0.75 \mathrm{~M} \, {HCl}

solution, the mass of sodium hydroxide left unreacted is equal to

View answer and explanation

Correct option: A

250 \mathrm{~mg}

Option A (250 mg) is correct because after reacting 1 g of NaOH with 25 mL of 0.75 M HCl, 250 mg of NaOH remains unreacted.

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