JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

f(\alpha)=\int_1^\alpha \frac{\log _{10} t}{1+t} d t, \alpha>0

, then

f\left(e^3\right)+f\left(e^{-3}\right)

is equal to:

View answer and explanation

Correct option: D

\frac{9}{2 \log _e(10)}

Option D (

\frac{{9}}{{2 \log_e(10)}}

) is correct because after substituting and simplifying the integral, we arrive at this result.

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