JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1

The integral

\int\limits_{0}^{1 / a} \frac{\log (1+a x)}{1+a^2 x^2} \mathrm{~d} x(a>0)

is equal to

View answer and explanation

Correct option: C

\frac{1}{a}(\log 2) \frac{\pi}{8}

Option C (

\frac{1}{a}(\log 2) \frac{\pi}{8}

) is correct because after substitution and integration, the integral evaluates to

\frac{1}{a}(\log 2) \frac{\pi}{8}

More Questions from DEFINITE INTEGRATION

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