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JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

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An electric dipole having dipole moment 4×4 \times 10−9Cm10^{-9} \mathrm{Cm} makes an angle 30∘30^{\circ} with the direction of a uniform electric field of magnitude 5 ×104NC−1\times 10^4 \mathrm{NC}^{-1}. Calculate the magnitude of the torque acting on the dipole. Also find out work required to rotate the dipole to make angle 90∘90^{\circ} with the direction of the electric field.
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Correct option: B
3×10−4 J\sqrt{3} \times 10^{-4} \mathrm{~J}
Option B (3×10−4 J\sqrt{3} \times 10^{-4} \mathrm{~J}) is correct because it is the work required to rotate the dipole, calculated using the potential energy difference at the given angles.

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