NEET UG CHEMISTRY MCQ: SURFACE CHEMISTRY

1 Hard

1 of 1

Understanding +4 | -1

A negatively charged sol can be formed by peptizing a solutions of

View answer and explanation

Correct option: B

{AgI}

with

{KI}

Option B (

{AgI}

with

{KI}

) is correct because when

{KI}

is in excess,

I^-

ions are adsorbed onto the AgI precipitate, forming a negatively charged sol.

More Questions from SURFACE CHEMISTRY

Practice All Chapter MCQs →

10^{-3} \mathrm{M}

1 \mathrm{~mm}^3

2 \times 10^{13}

\mathrm{N}_{\mathrm{A}}=6 \times 10^{23}

\log \frac{{x}}{{m}}

\log {P}

\theta=45^{\circ}

0.5

\log {k}= 0.699,

\mathrm{g}

\log \;x/m\mathrm{ } \;vs.

\log \;P

19\;\mathrm{g/c}{\mathrm{m}^3}

{1.9 \times {{10}^{ - 4}}\;\mathrm{g}}

10\;\mathrm{ }nm

m{m^3}