JEE PHYSICS MCQ: NUCLEI

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Analyzing +4 | -1

Consider the binding energy of

{ }_{17} {Cl}^{35}

and

{ }_{15} {P}^{31}

are 287.67 MeV and

262.48 {MeV}

, respectively. Then,

View answer and explanation

Correct option: B

{ }_{15} {P}^{31}

is more stable than

{ }_{17} {Cl}^{35}

Option B is correct because the stability of a nucleus is determined by the binding energy per nucleon, and

{}_{15}P^{31}

has a higher binding energy per nucleon than

{}_{17}Cl^{35}

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