JEE CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

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Analyzing +4 | -1

The first second and third ionisation energies

\left( {{E_1},{E_2}\,\,and\,\,{E_3}} \right)

for an element are

7\,\,eV,12.5\,\,eV

and

42.5\,\,eV

respectively. The most stable oxidation state of the element will be

View answer and explanation

Correct option: D

+ 2

Option D (+2) is correct because the large jump in ionization energy after the second ionization indicates a stable +2 oxidation state.

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