The value of $\mathop {\lim }\limits_{x \to 0} \frac{{{{\sin }^2}2x}}{{{{\sin }^2}4x}}$ is

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

The value of

\lim\limits_{x \to 0} \frac{{{{\sin }^2}2x}}{{{{\sin }^2}4x}}

View answer and explanation

Correct option: C

\frac{1}{4}

Option C (1/4) is correct because by using the property

\lim_{x \to 0} \frac{{\sin x}}{x} = 1

, the limit evaluates to 1/4.

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