The value of $\mathop {\lim }\limits_{x \to \infty } {\left( {\frac{{{x^2} + 6}}{{{x^2} - 6}}} \right)^x}$ is given by

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

The value of

\lim\limits_{x \to \infty } {\left( {\frac{{{x^2} + 6}}{{{x^2} - 6}}} \right)^x}

is given by

View answer and explanation

Correct option: B

Option B (1) is correct because the limit can be evaluated by rewriting the expression and using the standard limit definition of

e

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