An unknown compound A has a molecular formula ${{\rm{C}}_4}{{\rm{H}}_6}$. When A is treated with excess of ${\rm{B}}{{\rm{r}}_2}$ a new substance B with formula ${{\rm{C}}_4}{{\rm{H}}_6}{\rm{B}}{{\rm{r}}_4}{\rm{\;}}$ is formed. A forms a white ppt. with ammoniacal silver nitrate solution. A may be :

JEE CHEMISTRY MCQ: HYDROCARBONS

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An unknown compound A has a molecular formula

{\mathrm{C}_4}{\mathrm{H}_6}

. When A is treated with excess of

\mathrm{B}{\mathrm{r}_2}

a new substance B with formula

{\mathrm{C}_4}{\mathrm{H}_6}\mathrm{B}{\mathrm{r}_4}\mathrm{\;}

is formed. A forms a white ppt. with ammoniacal silver nitrate solution. A may be :

View answer and explanation

Correct option: A

But-1-yne

The correct answer is But-1-yne because it has a terminal alkyne which reacts with ammoniacal silver nitrate to form a white precipitate, and the formula C4H6 suggests two degrees of unsaturation.

JEE CHEMISTRY MCQ: HYDROCARBONS

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