If area bounded by curve $f(x)$ and $x$-axis, $x=1$ to $x=b$ is $(b-1)$ $\sin (3 b+4)$, then $f(x)$ is

$3 x \cos (3 x+4)+\sin (3 x+4)$

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

If area bounded by curve

f(x)

and

x

-axis,

x=1

x=b

(b-1)

\sin (3 b+4)

, then

f(x)

View answer and explanation

Correct option: B

3(x-1) \cos (3 x+4)+\sin (3 x+4)

Option D (

3(x-1) \cos (3 x+4)+\sin (3 x+4)

) is correct because differentiating the area function gives the function f(x).

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