JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Easy

1 of 1

Application +4 | -1

The coordinates of the points

A

and

B

are

(a, 0)

and

(-a, 0)

respectively. If a point

P

moves so that

P A^{2}-P B^{2}=2 k^{2}

, when

k

is constant, then the equation to the locus of the point

P

, is

View answer and explanation

Correct option: B

2 a x+k^{2}=0

Option B (

2ax + k^2 = 0

) is correct because the equation represents a vertical line, derived from the given condition

PA^2 - PB^2 = 2k^2

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