Weight of ${\rm{FeS}}{{\rm{O}}_4}\left( {{\rm{mol}}{\rm{.wt}}{\rm{.}} = 152} \right)$ oxidized by 200 mL of 1 $N$ ${\rm{KMn}}{{\rm{O}}_4}$ solution is :

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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Weight of

\mathrm{FeS}{\mathrm{O}_4}\left( {\mathrm{mol}\mathrm{.wt}\mathrm{.} = 152} \right)

oxidized by 200 mL of 1

N

\mathrm{KMn}{\mathrm{O}_4}

solution is :

View answer and explanation

Correct option: A

30.4 g

Option A (30.4 g) is correct because it is calculated using the concept of gram equivalents and the balanced redox reaction.

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