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NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

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The orbital angular momentum for an electron revolving in an orbit is given by l(l+1)h2Ļ€\sqrt {l\left( {l + 1} \right)} \frac{h}{{2\pi }}. This momentum for an s-electron will be given by
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Correct option: B
Zero
Option B (Zero) is correct because for an s-electron, the azimuthal quantum number (l) is 0, and substituting l=0 into the formula l(l+1)h2Ļ€\sqrt {l\left( {l + 1} \right)} \frac{h}{{2\pi }} results in zero.

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