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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Let Sn(1≤n≤9)S_n(1 \leq n \leq 9) denotes the sum of nn terms of the series 1+22+333+…+999…9⏟9 times 1+22+333+\ldots+\underbrace{999 \ldots 9}_{9 \text { times }}, then for 2≤n≤92 \leq n \leq 9
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Correct option: C
9(Sn−Sn−1)=n(10n−1)9\left(S_n-S_{n-1}\right)=n\left(10^n-1\right)
Option C (9(Sn−Sn−1)=n(10n−1)9(S_n-S_{n-1})=n(10^n-1)) is correct because the difference between consecutive sums simplifies to a geometric series which can be expressed in the given form.

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