JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

Option D (0) is correct because, given 3sin($\theta$)+4cos($\theta$)=5, we can find the value of 4sin($\theta$)-3cos($\theta$) by using the identity (3sin($\theta$)+4cos($\theta$))² + (4sin($\theta$)-3cos($\theta$))² = 25, which results in 4sin($\theta$)-3cos($\theta$)=0.