The bond angle in ${{\rm{H}}_2}{\rm{S}}$ (for ${\rm{H}} - {\rm{S}} - {\rm{H}}$) is:

Greater than ${\rm{H}} - {\rm{Se}} - H$ and less than ${\rm{H}} - {\rm{O}} - {\rm{H}}$

Same as that of ${\rm{Cl}} - {\rm{Be}} - {\rm{Cl}}$ in $BeC{{\rm{l}}_2}$

Greater than ${\rm{H}} - {\rm{N}} - {\rm{H}}$ bond angle in ${\rm{N}}{{\rm{H}}_3}$

Same as ${\rm{ClSn}} - {\rm{Cl}}$ in $SnC{{\rm{l}}_2}$

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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Analyzing +4 | -1

The bond angle in

{\mathrm{H}_2}\mathrm{S}

(for

\mathrm{H} - \mathrm{S} - \mathrm{H}

) is:

View answer and explanation

Correct option: C

Greater than

\mathrm{H} - \mathrm{Se} - H

and less than

\mathrm{H} - \mathrm{O} - \mathrm{H}

The correct answer is C (Greater than H - Se - H and less than H - O - H) because bond angles decrease down the group due to increasing size and decreasing bond pair-bond pair repulsion.

JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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