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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1
If x<0x < 0, then tan⁡−1x+tan⁡−1(1/x)\tan ^{-1} x+\tan ^{-1}(1 / x) equals
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Correct option: C
−π/2-\pi / 2
The correct answer is C (−π/2-\pi / 2) because when x < 0, the identity tan⁡−1x+tan⁡−1(1/x)=−π/2\tan^{-1} x + \tan^{-1}(1/x) = -\pi/2 holds.

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