JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

The sequence

\left\{a_n\right\}

is a GP such that

\frac{a_4}{a_6}=\frac{1}{4} \quad \text { and } \quad a_2+a_5=216

. If the common ratio is positive, then the first term is

View answer and explanation

Correct option: A

Option A (12) is correct because solving the GP equations gives the first term as 12.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

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(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

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a, b, c

\frac{3}{4}