JEE PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

Position of a particle at any instant

t

is given

\vec{r}=3 \hat{i}+2 t^2 \hat{j}+5 \hat{k}

, Its velocity at same instant will be:

View answer and explanation

Correct option: C

3\hat{i}+4 t \hat{j}

Option C (

3\hat{i}+4 t \hat{j}

) is correct because velocity is the derivative of the position vector with respect to time.

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

0^{\circ}

90^{\circ}

\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0

\mathbf{a}

\mathbf{b}

\theta

\left(90^{\circ}-\theta\right)

39.2 \mathrm{~ms}^{-1}

50 \mathrm{~m}

{g}=9.8 \mathrm{~ms}^{-2}