JEE PHYSICS MCQ: WAVE OPTICS

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Application +4 | -1

A long narrow horizontal slit is placed

1 \mathrm{~mm}

above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen

1.0 \mathrm{~m}

away from the slit. Find the fringe-width if the light used has a wavelength of

700 \mathrm{~nm}

View answer and explanation

Correct option: A

0.35 mm

The correct answer is A (0.35 mm) because the fringe width in Lloyd's mirror experiment is calculated using the formula

\frac{\lambda D}{d}

, where d is twice the distance between the slit and the mirror.

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