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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
Let function FF be defined as F(x)=∫1xettdt,x>0F(x)=\int\limits_{1}^x \frac{\mathrm{e}^t}{\mathrm{t}} \mathrm{dt}, x > 0 then the value of the integral ∫1xett+adt\int\limits_{1}^x \frac{\mathrm{e}^t}{t+a} d t, where a>0a > 0, is:
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Correct option: D
e−a[F(x+a)−F(1+a)]e^{-a}[F(x+a)-F(1+a)]
Option D (e−a[F(x+a)−F(1+a)]e^{-a}[F(x+a)-F(1+a)]) is correct because it is the result obtained after applying a suitable substitution and using the given definition of the function F(x).

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