JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

The point on the graph

y=\log _2 \log _6\left\{2^{\sqrt{(2 x+1)}}+4\right\},

whose

y

-coordinate is 1 is

View answer and explanation

Correct option: D

(12,1)

Option D ((12,1)) is correct because substituting y=1 into the equation and solving for x yields x=12.

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