NEET UG PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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A wire of length 50 cm is moving parallel to itself with a speed of

1 \mathrm{~m} / \mathrm{s}

in a perpendicular magnetic field of

2 \times 10^{-4}

tesla. The emf developed across its two ends is:

View answer and explanation

Correct option: D

Zero

Option D (Zero) is correct because the wire is moving parallel to itself in the magnetic field, meaning there is no change in magnetic flux through the area it encloses.

More Questions from ELECTRO MAGNETIC INDUCTION

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Assertion (A): Whenever the magnetic flux linked with a closed coil changes there will be an induced emf as well as an induced current.

Reason (R): According to Faraday, the induced emf is inversely proportional to the rate of change of magnetic flux linked with a coil. The coefficient of mutual inductance of two coils is

6\,\,mH

. If the current flowing in one is

2\,\,ampere

, then the induced e.m.f. in the second coil will be The induced emf cannot be produced by: Consider the statements:
(I)If magnetic field,

\mathrm{B = 0}

, then magnetic flux is also zero.
(II)If magnetic flux,

\phi = 0,

then magnetic field is also zero. The coefficient of self inductance of a solenoid is 0.18 mH. If a rod of soft iron of relative permeability 900 is inserted, then the coefficient of self inductance (in mH ) will become nearly: A uniformly wound solenoidal coil of self inductance

1.8 \times {10^{ - 4}}

H and resistance 6 Ω is broken up into two identical coils. These identical coils are then connected in parallel across a 12 V battery of negligible resistance. The time constant of the current in the circuit 