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JEE CHEMISTRY MCQ: STATES OF MATTER

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Let the most probable velocity of hydrogen molecules at a temperature of t∘C\mathrm{t}^{\circ} \mathrm{C} be V0\mathrm{V}_0. When the temperature is raised to (2t+273)∘C(2 \mathrm{t}+273)^{\circ} \mathrm{C} the new rms velocity is (suppose all the molecules dissociate into atoms at latter temperature)
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Correct option: B
6 V0\sqrt{6} \mathrm{~V}_0
The correct answer is B (6 V0\sqrt{6} \mathrm{~V}_0) because the new RMS velocity can be found by relating it to the initial most probable velocity, considering the dissociation of hydrogen molecules into atoms.

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